Split words into two words from wordlist

[jonathan11]

I have a wordlist with about 10.000.000 lines that looks like;

EA5894|5F96A82BAE
8DAE99|F4B95B07D1
8370BE|B437EBC243
BBF8C2|2C9933FC8D
..................

Is there any script or similar out there that would allow me to remove the first 7 characters on every line?
For example to make the above list to look like:

5F96A82BAE
F4B95B07D1
B437EBC243
2C9933FC8D
..................

Any help would be greatly appreciated!

[Liuser]

cat [filename] | cut -d"|" -f2

[jonathan11]

cat [filename] | cut -d"|" -f2

That was exactly what I was looking for, thanks a bunch!

[espreto]

cat [filename] | cut -d"|" -f2

Small improvement.

root@bt:~# cat wordlist | cut -d"|" -f2 > wordlist2; cat wordlist2
...................
5F96A82BAE
F4B95B07D1
B437EBC243
2C9933FC8D
...................
root@bt:~#

Regards,