Can I mix the contains of two wordlist files together?

I am using crunch to generate wordlists, but I want to mix the contains of two of my wordlist files, can I do that using some kind of program? You know that no one want to do that manually......:o

Try a combination of "cat" and "sort -u" (others will tell you "sort | uniq").

If you seriously can't work it out from there come back to us.

Quote:

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Originally Posted by Gitsnik

Try a combination of "cat" and "sort -u" (others will tell you "sort | uniq").

If you seriously can't work it out from there come back to us.

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Thank you Gitsnik, But the combination I mean is for example, there are dict A and dict B. Dict A got "a b c" in it, and dict B got "1 2 3" in it. after mix I got a dict C, which is contain "a1 a2 a3 b1 b2 b3 c1 c2 c3 1a 2a 3a...................." can "cat" and "sort -u" achieve this? :confused:

Quote:

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Originally Posted by voochee

can "cat" and "sort -u" achieve this? :confused:

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Strictly no, but then you're not necessarily doing something many people would elect to do.

The following code I literally just hacked up in this reply panel, I haven't tested it nor will I provide support on it. It contains only very basic perl code, so if you can not read it I suggest you do one of those "learn perl in 24 hours" courses and then figure it out from there.

The essence of the code is: read a line from file 1, read a line from file 2, as you read each character from file 1, insert the same character (position) from file 2 and print it out.

Assuming no typo's and that I understood you properly this time around, it should do what you wish, again - no willingness to provide support.

Code:

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#!/usr/bin/perl

open(FILE_ONE, "fileone.txt");
open(FILE_TWO, "filetwo.txt");
while($f1l = <FILE_ONE>) {
  $f2l = <FILE_TWO>;
  chomp($f1l);
  chomp($f2l);
  my @f1a = split //, $f1l;
  my @f2a = split //, $f2l;
  my $i = 0;
  foreach my $char (@f1a) {
    print $char, $f2a[$i];
    $i += 1;
  }
  print "\n";
}
close(FILE_ONE);
close(FILE_TWO);

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Quote:

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Originally Posted by Gitsnik

Strictly no, but then you're not necessarily doing something many people would elect to do.

The following code I literally just hacked up in this reply panel, I haven't tested it nor will I provide support on it. It contains only very basic perl code, so if you can not read it I suggest you do one of those "learn perl in 24 hours" courses and then figure it out from there.

The essence of the code is: read a line from file 1, read a line from file 2, as you read each character from file 1, insert the same character (position) from file 2 and print it out.

Assuming no typo's and that I understood you properly this time around, it should do what you wish, again - no willingness to provide support.

Code:

---

#!/usr/bin/perl

open(FILE_ONE, "fileone.txt");
open(FILE_TWO, "filetwo.txt");
while($f1l = <FILE_ONE>) {
  $f2l = <FILE_TWO>;
  chomp($f1l);
  chomp($f2l);
  my @f1a = split //, $f1l;
  my @f2a = split //, $f2l;
  my $i = 0;
  foreach my $char (@f1a) {
    print $char, $f2a[$i];
    $i += 1;
  }
  print "\n";
}
close(FILE_ONE);
close(FILE_TWO);

---

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Thank you very much, I will learn perl in the next 24 hours :)

This looks like fun, I'm gonna give it a go in C++:

Code:

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#include <iostream>    /* cout, endl */
#include <fstream>    /* ifstream */
#include <string>      /* string */
using std::cout;
using std::endl;
using std::ifstream;
using std::string;

int main(int argc, char **argv)
{
    if ( 3 != argc )
    {
        cout << "Usage: " << argv[0] << " in1.txt in2.txt > out.txt" << endl;
        return 0;
    }

    ifstream a( argv[1] ); /* Open the first file */

    if ( !a.is_open() )
    {
        cout << "Could not open " << argv[1] << endl;
        return 0;
    }

    string str_a;

    while ( a >> str_a )
    {
        string str_b;

        ifstream b( argv[2] );

        if ( !b.is_open() )
        {
            cout << "Could not open " << argv[2] << endl;
            return 0;
        }

        while ( b >> str_b )
        {
            cout << str_a << str_b << endl;
        }
    }
}

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Compile as follows:

Code:

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g++ concat.cpp -D NDEBUG -s -O3 -o concat

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And run as follows:

Code:

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./concat in1.txt in2.txt > out.txt

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Virchanza I think your method produces a different output to mine (It has been a while since I read << notation in C++ though so I could be wrong).

Mine should produce:

f1: abc
f2: 123
out: a1b2c3

But yours produces:

abc123 from the same input (at least on my FreeBSD test box).

A good chance for you to have a play with arrays. You might even notice that if you have only two characters in the second line, but 3 in the first you may run into some buffering issues when you do it.

Edit: Oh yes, and I intentionally didn't blow out the lines properly to be a1 b1 c1 a2 b2 c2, but the basic premise is there - you just need to add an extra loop somewhere and shift the choice of i.

Quote:

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Originally Posted by Gitsnik

Virchanza I think your method produces a different output to mine (It has been a while since I read << notation in C++ though so I could be wrong).

Mine should produce:

f1: abc
f2: 123
out: a1b2c3

But yours produces:

abc123 from the same input (at least on my FreeBSD test box)

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Your FreeBSD box is right (the code I posted is fully-portable so it will work on any machine).

I'm pretty sure that the OP meant the following...

in1.txt as follows:

Code:

---

a
b
c

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in2.txt as follows:

Code:

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1
2
3

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So if you append every word of the second file to every word of the first file, you get:

Code:

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a1
a2
a3
b1
b2
b3
c1
c2
c3

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That's what my little program does.

Quote:

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Originally Posted by Virchanza

That's what my little program does.

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You are probably correct then, I may have lost it in translation again.